Finding the TP?
I was reading this writeup (ECU Tuning) trying to soak in some info from it. There is one section in particular that stumped me though. This passage:
"First is the equation for TP: (VQ x K Value / CAS Value) / Number of Cylinders
VQ is the value taken from the VQ Table. CAS is the rpm / 50 x 256.
Here is an example:
On stock injectors at a light throttle and 2500rpms, the MAF is sending back a 2.56v signal (example only). That voltage falls on the 32nd block of the VQ Table. That value is 1B39hex or 6969dec. So our equation will look like this:
[ 6969 x 288 / (2500rpms x 50 / 256) / 6 cylinders = TP ]
So 2007072 / 12800 = 156.8 - and since this is the total amount of fuel needed for the whole engine, we divide it by the number of cylinders (156.8 / 6cyl). That gives us our TP Value of 26dec (or 1Ahex) . How significant is this??? If we know the MAF voltage and the rpm we can calculate the TP and find the exact points being accessed on our Timing and Fuel Maps! So lining up the TP value of 26dec (1Ahex) and the rpm of 2500 we can find the corresponding block (or block of 4 points if it does not fall exactly on 1 point) on the maps under those engine conditions. With a data logger like a Conzult we can quickly find and adjust or fix points on the maps. Even without data logging we can still find points using a good voltage tester and remembering rpms."
I kept trying this equation to suit my B13 ECU, but I kept getting astronomical figures due to the B13 K value (31,xxx). Here's one example I tried, following the above formula:
Using an E60 MAF, at a reading of 2.24 Volts, the MAF value is: 5426
The K value is: 36000
(The first formula given for finding CAS is correct (CAS is the rpm / 50 x 256), the second time it is shown wrong (2500rpms x 50 / 256)
My CAS is: 3,200 rpm / 50 x 256 = 16384
So, that gives me:
(5426 x 36000) / (3200 / 50 x 256) / 4
-or-
195336000 / 16384 / 4 = 2981 (rounded)
A TP of 2981??? Is there something more to this, or is this equation wrong? I have a feeling maybe the CAS may not quite apply to a B13?
"First is the equation for TP: (VQ x K Value / CAS Value) / Number of Cylinders
VQ is the value taken from the VQ Table. CAS is the rpm / 50 x 256.
Here is an example:
On stock injectors at a light throttle and 2500rpms, the MAF is sending back a 2.56v signal (example only). That voltage falls on the 32nd block of the VQ Table. That value is 1B39hex or 6969dec. So our equation will look like this:
[ 6969 x 288 / (2500rpms x 50 / 256) / 6 cylinders = TP ]
So 2007072 / 12800 = 156.8 - and since this is the total amount of fuel needed for the whole engine, we divide it by the number of cylinders (156.8 / 6cyl). That gives us our TP Value of 26dec (or 1Ahex) . How significant is this??? If we know the MAF voltage and the rpm we can calculate the TP and find the exact points being accessed on our Timing and Fuel Maps! So lining up the TP value of 26dec (1Ahex) and the rpm of 2500 we can find the corresponding block (or block of 4 points if it does not fall exactly on 1 point) on the maps under those engine conditions. With a data logger like a Conzult we can quickly find and adjust or fix points on the maps. Even without data logging we can still find points using a good voltage tester and remembering rpms."
I kept trying this equation to suit my B13 ECU, but I kept getting astronomical figures due to the B13 K value (31,xxx). Here's one example I tried, following the above formula:
Using an E60 MAF, at a reading of 2.24 Volts, the MAF value is: 5426
The K value is: 36000
(The first formula given for finding CAS is correct (CAS is the rpm / 50 x 256), the second time it is shown wrong (2500rpms x 50 / 256)
My CAS is: 3,200 rpm / 50 x 256 = 16384
So, that gives me:
(5426 x 36000) / (3200 / 50 x 256) / 4
-or-
195336000 / 16384 / 4 = 2981 (rounded)
A TP of 2981??? Is there something more to this, or is this equation wrong? I have a feeling maybe the CAS may not quite apply to a B13?