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Thread: Attempting to learn :)

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Posts: 1-10 of 11
2009-10-07 23:21:41
#1
Attempting to learn :)
Working on a bin.

Started with Stock ve inj's (333). Going to be using 480's. Just wanted to verify some math.

480/333= 1.44144144 repeating.
1.44144144 * 28646 (original K value for inj) = 41292

New k value = 41292


Or did i somehow confuse myself on simple mathematics lol
2009-10-08 03:46:32
#2
You divide Old/New Injector = 333/480=.69375
Old K x Divided %
new k = 19873.1625

That's from this injector worksheet I have says
2009-10-08 19:17:01
#3
I dont intend on sounding tarded so i apologize if this leads to such conclusion but, i dont understand why you would divide the old injectors by the new ones. Your method leaves a lower K value for a higher injector, shouldnt it be vice versa?


New inj/Old would yeild the factor of increase


http://www.sr20-forum.com/tuning/15775-noob-tuning-his-own-car-calum-rt.html#post206603
2009-10-08 20:11:58
#4
Lower K value is not a bad thing. K value is a multiplier of the Injector size vs the Map you have, plus some other things. My 370 CC K value was like 240, while stock one was over 300.

Oh and numbers will vary greatly between B13's and B14's.
2009-10-08 21:05:45
#5
So the 19873 number would be the correct K value as Likethemovies posted?
2009-10-09 04:36:32
#6
Haven't had the time to do the math. If you follow the formula couple times and get the same result then yes.

Then you can upload it and try it out. Having a wideband is a must though.
2009-10-09 05:00:16
#7
DL a like 740cc bin or something high like that and see if it's higher or not? In that thread I duno why they would be downgrading injectors?

550/633? wouldn't they go 633/550 if it was new to old?
2009-10-09 15:29:00
#8
From what i took he wasnt downgrading his injector size. The Bin he was using was programmed for bigger injectors than his own.

Part of why im completely confused on this and posted it.



Vadim, I dont know if im doing the formula correctly. So far I have had multiple sources tell me a different way so im not certain if im doing it right.


Option A- Old Inj / New Inj = X * Original K Value
Option B- New Inj/ Old Inj = X * Original K Value


Both options yield different values.
2009-10-09 15:57:44
#9
Simple algebra will show that flipping one side of an equation will yeild different values.

I view it from the standpoint of throughput.

Bigger would need less to give the same amount of throughput.

See if this helps you. (Page 6)
nissan_ecu_tuning_basics.pdf
2009-10-09 16:22:46
#10
Originally Posted by donshou
Simple algebra will show that flipping one side of an equation will yeild different values.

I view it from the standpoint of throughput.

Bigger would need less to give the same amount of throughput.

See if this helps you. (Page 6)
nissan_ecu_tuning_basics.pdf



Thank you sir, that PDF is downloaded and saved and i have my answer.
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